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fix: openid 不一致清除缓存时保留 URL 参数重新登录（避免跳到无身份登录页）

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This commit is contained in:
Karlcarlo
2026-07-31 15:22:04 +08:00
parent 4e4df248ca
commit 21916c565a
1 changed files with 5 additions and 3 deletions
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8
frontend/src/app/routes.tsx
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@@ -32,14 +32,16 @@ function ProtectedRoute() {
return <Navigate to={`/?token=${encodeURIComponent(urlToken)}`} replace />; return <Navigate to={`/?token=${encodeURIComponent(urlToken)}`} replace />;
} }
// URL 中有 openid 且与本地缓存的 token 中的 openid 不一致 → 清除缓存重新登录 // URL 中有 openid 且与本地缓存的 token 中的 openid 不一致 → 清除缓存，保留 URL 参数重新登录
if (urlOpenid && token) { if (urlOpenid && token) {
try { try {
const payload = decodeToken(token); const payload = decodeToken(token);
if (payload.openid !== urlOpenid) { if (payload.openid !== urlOpenid) {
console.log('[auth] openid 不一致: URL=' + urlOpenid + ', cache=' + payload.openid + '，清除缓存'); console.log('[auth] openid 不一致: URL=' + urlOpenid + ', cache=' + payload.openid + '，清除缓存，保留 URL 参数重新登录');
clearToken(); clearToken();
return <Navigate to="/" replace />; // 保留 openid/unionid 等参数跳登录页，LoginPage 会用 URL 的 openid 直接登录
const search = new URLSearchParams(window.location.search).toString();
return <Navigate to={search ? `/?${search}` : "/"} replace />;
} }
} catch (e) { } catch (e) {
console.warn('[auth] token 解码失败', e); console.warn('[auth] token 解码失败', e);